24.7 Tail Concentration Functions

Measure how much probability is concentrated in the tails

24.7.1 Left Tail Concentration Function

What is the probability that \(U\) is small given that \(V\) is small

\[L(z) = P(U < z \mid V < z) = P(V < z \mid U < z)\]

  • Works both ways can do \(L(z) = P(V < z \mid U < z)\) as well

Left tail concentration function

\[\begin{equation} L(z) = \dfrac{C(z,z)}{z} \tag{24.26} \end{equation}\]

LTC function for Independent copula:

\[\begin{equation} L(z) = z \tag{24.27} \end{equation}\]
  • Graph this to 0.5 because all copulas have \(L(1) = 1\)

  • See Graph (1) in fig. 24.1

24.7.2 Right Tail Concentration Function

What is the probability that one variable is large given that the other variable is large

\[R(z) = P(U > z \mid V > z) = P(V > z \mid U > z)\]

Right tail concentration function

\[\begin{equation} R(z) = \dfrac{1 - 2z + C(z,z)}{1-z} \tag{24.28} \end{equation}\]

RTC function for Independent copula:

\[\begin{equation} R(z) = 1 - z \tag{24.29} \end{equation}\]
  • Graph this from 0.5 to 1.0 because all copulas has \(R(0) = 0\)

  • See Graph (2) in fig. 24.1

24.7.3 LR Graph

Combine the 2 above we have the tail concentration graph or the LR graph

  • See Graph (3) in fig. 24.1

The independent copula = product copula

Tail concentration graph

Figure 24.1: Tail concentration graph

  • Graph (4) it approaches 0 on the left and right

  • Graph (5) asymmetric, right limit is not 0 (converges about 0.5)

  • Graph (6) asymmetric, right limit is not 0, and higher than Gumbel. Has the thinnest left tail

  • Graph (7) it approaches 0 on the left and right but slower, simply because we couldn’t calculate the tail so deep

As the \(\tau\) gets higher, we can start the see the difference between them

Table 24.2: Limit of right tail concentration function \(R = \lim \limits_{z \rightarrow 1} R(z)\)
Copula \(R\) \(\tau\)
Gumbel \(2 - 2^{1/a}\) \(1 - \dfrac{1}{a}\)
HRT \(2^{-a}\) \(\dfrac{1}{2a + 1}\)
Normal 0 \(\dfrac{2 \arcsin(a)}{\pi}\)
Frank 0 Complicated…
PP Power \(\dfrac{1}{1 + a}\)
  • Table is not on syllabus but just for information